What would be the kinetic energy of 1 g of nitrogen gas at 770C. Given R = 8.31 J mol-1 K-1
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Answered by
37
Given :
mass of nitrogen :M=28
Temperature =T=77°C=77+273=350K
Gas constant R=8.31 /mol K
K.E of 1 g of Nitrogen=K.E=3RT/2M
=3x8.31x350/2x28
=155.8J
∴Kinetic energy of 1 g of nitrogen gas at 77°C is 155.8J
mass of nitrogen :M=28
Temperature =T=77°C=77+273=350K
Gas constant R=8.31 /mol K
K.E of 1 g of Nitrogen=K.E=3RT/2M
=3x8.31x350/2x28
=155.8J
∴Kinetic energy of 1 g of nitrogen gas at 77°C is 155.8J
Answered by
5
ANSWER
.............
MASS = 28
TEMPERATURE = 77° + 273 = 350
R = 8.31
1 GRAM OF NITROGEN
= 3 * 8.31 * 350 / 2 * 28
= 155.8 JOULE
.............
MASS = 28
TEMPERATURE = 77° + 273 = 350
R = 8.31
1 GRAM OF NITROGEN
= 3 * 8.31 * 350 / 2 * 28
= 155.8 JOULE
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