Question

what would be the last term of an a.p with 10 terms whose second term is -23 and the third term is -35?​

Answer 1

Please see the image description

Answer 2

Answer:

a2 = -23

a3 = -35

a3 - a2 = d

d = -35 - (-23)

d = -12

an = a + (n - 1)d

a10 = -23 + (10 - 1)-12

a10 = -23 - 108

a10 = -131