What would be the simple interest obtained on an amount of Rs. 6535 at the rate 10% after 6 years ?
Answers
Answered by
4
AnSwEr -:
_____________________________
Simple Interest = ₹ 3921
_______________________________
Explanation-:
Formula of Simple Interest-:
S.I = P x R x T
Here ,
P = initial principal balance
r = annual interest rate
t = time (in years)
____________________________
Given ,
P = ₹ 6535
R = 10 % or 10/100
T= 6 years
•To find ,
Simple Interest = P x R x T
•Calculate-:
= 6535 x 10 x 6 / 100
= 6535 x 6 / 10
= 39210 / 10
= 3921
•Simple Interest = ₹ 3921
______________________________
•Some formulas related to question -:
•Simple Interest = (P × R × T) ÷ 100
•Amount = SI + P
•A = {(P × R × T) ÷ 100} + P
Here ,
SI -: Simple Interest
A -: Amount/Future Value
P -: Principal Amount
R -: Rate of Interest per annum
T -: Time in years
_______________________________
_____________________________
Simple Interest = ₹ 3921
_______________________________
Explanation-:
Formula of Simple Interest-:
S.I = P x R x T
Here ,
P = initial principal balance
r = annual interest rate
t = time (in years)
____________________________
Given ,
P = ₹ 6535
R = 10 % or 10/100
T= 6 years
•To find ,
Simple Interest = P x R x T
•Calculate-:
= 6535 x 10 x 6 / 100
= 6535 x 6 / 10
= 39210 / 10
= 3921
•Simple Interest = ₹ 3921
______________________________
•Some formulas related to question -:
•Simple Interest = (P × R × T) ÷ 100
•Amount = SI + P
•A = {(P × R × T) ÷ 100} + P
Here ,
SI -: Simple Interest
A -: Amount/Future Value
P -: Principal Amount
R -: Rate of Interest per annum
T -: Time in years
_______________________________
Answered by
1
SI= 6535*10*6/100
=3921
=3921
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