What would be the value of 'g' on earths surface if its mass was twice -and its radium half of what it is now? mass of earth = 6*10^24; radius =6.4*10^6. please try to explain this sum in detail by solving it on your book by sending phoTO
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g=GM/R²
M'=2M
R=R/2
g'=GM'/R'²
=G*2M/R²/4
=8GM/R²
=8g
as g=9.8 m/s²
therefore
g'=8g
=8*9.8
=78.4 m/s²
hope this helps.
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