Question

what would be the value of 'g' on the surface of the earth if its mass twice and its radius half of what it is now ?​

Answer 1

Explanation:

Hey there,

g=GM/r^2

Now ,g(new)=G(2M)/(r/2)^2

= GM/r^2 ×8=8g.

Hence, it will b'come 8 times of 

present g and u are going to get 

crushed on this new gravity.

Hope it helps