Question

What would be the volume of 6.00 g of helium gas at STP?

Answer 1

$\huge{\ulcorner{\red{\mathcal{ANSWER}}}}\rfloor$

$\boxed{\star \textsf{ First we should know}}$

$\textbf{ What is STP ? }$

$\textsf{ Standard Temperature and Pressure}\\ \textsf{ Where temperature = 273 k } \\ \textsf{ Pressure = 1 atm }$

$\textbf{ What is the molecular mass }\\ \textbf{of Helium ? }$

$\sf{ = 4\: gram }$

$\textbf{ How to find out Number }\\ \textbf{ of Moles ?}$

$\sf{ \dfrac{Given\:Mass}{Molar\:Mass}}$

$\textbf{ What is volume of 1 mole } \\ \textbf{ of gas at STP ? }$

$\sf{ = 22.4 \: litres}$

$\boxed{\star \textsf{ Now solution}}$

$\sf{Given\: mass = 6\: gram }$

$\sf{So\: Number\: of \: Moles = \dfrac{6}{4}} \\\\ \sf{= 1.5 \: Moles}$

$\sf{So\: Volume\: of\:gas}$

$\sf{ No. \: of \: Moles \times 22.4 }\\\\ \sf{ = (1.5) \times (22.4) } \\\\ \sf{= 33.6 }$

$\textbf{ So volume of Helium gas = 33.6 litres}$

Answer 2

33.6 litres

Explanation:

Assuming that helium behaves as an ideal gas, we know that a mole of ideal gas occupies 22.4 litres at STP.

The atomic weight of helium is 4 g/mol, so 6 g is 1.5 moles.

The volume occupied at STP, therefore, is 22.4 x 1.5 = 33.6 litres.