Question

what would the volume of a gas be at -150˚C, if it had a volume of 693mL at 45˚C?

Answer 1

Answer:

V1/T1=V2/T2

T1=-150=273-150=123K

T2=45=45+273=318K

V2=693*10^-3

V1=(V2/T2)*T1

V1=693*10^-3*123/318