whatvis the oxidation number of N in hydrazoic acid
Answers
Answered by
1
Oxidation state between similar atom results in zero oxidation number i.e. between atoms 2 and 3 and between atoms 3 and 4. So now we have to calculate the oxidation number between 1 and 2 i.e between H and N. Since there is 1 bond formed -1 oxidation number will be given to more electronegative atom, which here is N and +1 will be given to more electropositive atom which here is H. Finally we can conclude that H will have +1, N(1) will have -1 and N(2,3) will both have 0 oxidation number. Since -1 is the total oxidation number between 3 N atoms, the average oxidation number on N will be -1/3.
We can use a equation to solve this. Let the average charge on N atom is x. The oxidation number on 3 N atoms will be 3x. H will have +1 oxidation number as discussed above. Since the total charge on this whole molecule is 0, we can make a equation in which we balance the total oxidation state of the atom to the total charge on the molecule, i.e. 0
Total oxidation no. = Net charge on atom.
Oxidation number on H + Total Oxidation number on N = 0
+1 + 3x =0
By solving, we get the average oxidation number is -1/3, which is same as above.
We can solve by any method, but the second one is my preferred, as there is less chance of mistakes in that method.
We can use a equation to solve this. Let the average charge on N atom is x. The oxidation number on 3 N atoms will be 3x. H will have +1 oxidation number as discussed above. Since the total charge on this whole molecule is 0, we can make a equation in which we balance the total oxidation state of the atom to the total charge on the molecule, i.e. 0
Total oxidation no. = Net charge on atom.
Oxidation number on H + Total Oxidation number on N = 0
+1 + 3x =0
By solving, we get the average oxidation number is -1/3, which is same as above.
We can solve by any method, but the second one is my preferred, as there is less chance of mistakes in that method.
Similar questions