Question

whatwhat is ratio of average kinetic energy of oxygen molecule to that of ozone molecule at 27 degree Celsius ​

Answer 1

Answer:

Ratio is 2:3

Explanation:

Total kinetic energy = n (3/2 RT0)

where n = Number of moles of the gas

R = Gas constant

T = Absolute temperature

Now molecular formula is of Oxygen is O2 = 2 moles of oxygen

And  molecular formula of Ozone is i O3 = 3 moles of oxygen

Now in kinetic energy formula, Put first n = 2 and then n=3 we get ratio 2:3