When 0.2M acetic acid is neutralised with 0.1M NaOH in 0.5 litre of water the resulting solution is slightly alkaline. Calculate the pH of the resulting solution. K a for CH 3 COOH=1.8×10 −5 .
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CHEMISTRY
When 0.2M acetic acid is neutralised with 0.1M NaOH in 0.5 litre of water the resulting solution is slightly alkaline. Calculate the pH of the resulting solution. K
a
for CH
3
COOH=1.8×10
−5
.
November 22, 2019avatar
Bellatrix Sree
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ANSWER
0.2M acetic acid will form 0.2M CH
3
COONa and 0.5 litre of water. Hence, concentration of sodium acetate [CH
3
COONa]=0.1molL
−1
CH
3
COO
−
+H
2
O⇌CH
3
COOH+OH
−
C(1−x) CxCx
K
h
=
(1−x)
Cx
2
=Cx
2
(1−x)→1
K
h
=
K
a
K
w
=
1.8×10
−5
1×10
−14
=5.5×10
−10
So, K
h
=Cx
2
=5.5×10
−10
or x
2
=55×10
−10
or x=7.42×10
−5
[OH
−
]=Cx=7.42×10
−5
×0.1=7.42×10
−6
M
[H
+
]=
[OH
−
]
K
w
=1.3477×10
−9
M
pH=−log[H
+
]=8.87
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