Question

When 1.5g of a non volatile solute was dissolved in 90g of benzene, the boiling point of benzene raised from 353.23K to 353.93K. Calculate the Molar mass of the solute. (Kb for benzene=2.52K Kg/mol)

Answer 1

Answer:

molecular mass is 60

Explanation:

we know that ∆Tb = 1000Kb n/W

353.93- 353.23= 1000× 2.52× 1.5/m90

0.7= 42/ m

m= 60