Question

When 1 mol CrCl3 ⋅6H2O is treated with excess of AgNO3 , 3 mol of AgCl are obtained. The formula of the

complex is:

a) [CrCl3 (H2O)3 ]⋅3H2O
b) [CrCl2 (H2O)4 ]Cl⋅2H2O

c) [CrCl(H2O)5 ]Cl2 ⋅H2O
d) [Cr(H2O)6 ]Cl3

​

Answer 1

Answer:

crclh20√

Explanation:

crcl doesn't multiplies h 20