Question

when 1 ohm and 1 by 4 ohm and 2 by 3 ohm are connected in parallel combination then calculate is equivalent resistance​

Answer 1

Answer:

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Answer 2

Given that : R1 = 1 ohm, R2 = 1/4 ohm and R3 = 2/3 ohm

As we know that : In parallel combination

$\frac{1}{</strong><strong>R</strong><strong>} = \frac{1}{ </strong><strong>R</strong><strong>_{1} } + \frac{1}{ </strong><strong>R</strong><strong>_{2}} + \frac{1}{ </strong><strong>R</strong><strong>_{3}} \\ \\ = > \frac{1}{</strong><strong>R</strong><strong>} = \frac{1}{1} + \frac{1}{ \frac{1}{4} } + \frac{1}{ \frac{2}{3} } \\ \\ = > \frac{1}{</strong><strong>R</strong><strong>} = 1 + 4 + \frac{3}{2} \\ \\ = > \frac{1}{</strong><strong>R</strong><strong>} = \frac{2 + 8 + 3}{2} = \frac{13}{2}$

So, the equivalent resistance will be 2/13 ohm.

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