When 10% momentum is increased how much kinetic energy is increased?
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Answered by
0
Answer:
E =10% change in K. E. New K. E. = 1/2 m (1.1 v)² = 1.21 of original K. E.
Answered by
2
Answer:
E =10% change in K. E. New K. E. = 1/2 m (1.1 v)² = 1.21 of original K. E.
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