When 10% momentum is increased how much kinetic energy is increased?
Answers
Answered by
0
Answer:
E =10% change in K. E. New K. E. = 1/2 m (1.1 v)² = 1.21 of original K. E.
Answered by
2
Answer:
E =10% change in K. E. New K. E. = 1/2 m (1.1 v)² = 1.21 of original K. E.
Similar questions