when 100 g of calcium carbonate decompose completely then 56g of calcium carbonate is obtained.
calculate the amount of carbon dioxide formed and also find the ratio of calcium oxide and carbon dioxide.
Answers
Answer:
approx .80g.
Explanation:
We need a stoichiometric reaction that represents the decomposition of calcium carbonate:
C
a
C
O
3
(
s
)
+
Δ
→
C
a
O
(
s
)
+
C
O
2
(
g
)
↑
⏐
And thus calcium oxide and calcium carbonate are present in equimolar amounts:
Moles of calcium oxide
=
44.5
⋅
g
56.08
⋅
g
⋅
m
o
l
−
1
=
0.794
⋅
m
o
l
.
Given the stoichiometry of the reaction, an equimolar quantity of calcium carbonate MUST have been present.
This represents a mass of
0.794
⋅
m
o
l
×
100.09
⋅
g
⋅
m
o
l
−
1
≅
80
⋅
g
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ANSWER : The above equation follows law of conservation of mass.
Explanation:
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
We are given:
Mass of calcium carbonate = 100 grams
Mass of calcium oxide = 56 grams
Mass of carbon dioxide = 44 grams
Total mass on reactant side = 100
Total mass on product side = 56 + 44 = 100 g
Hence, the above equation follows law of conservation of mass.
