Question

When 100ml of M/10 H2so4 is mixed with 500ml of M/10 NaOH then nature of resulting solution and normality of excess of reactant left is??

Answer 1

$M_{HCl}$=moles*1000/v(ml)
mole=0.01
eq HCl = moles *n factor = 0.01*2 =0.02
$M_{NaOH}$=moles*1000/v(ml)
mole=0.05
eq NaOH = moles *n factor = 0.05*1 =0.05
eq NaOH> eq HCl so the nature of th product is basic and excess left eq 0.02
N left NaOH = 0.003*500 = 1.5