Question

When 100ml of n/10 naoh are added to 50 ml of n/5 hcl ,the ph of the redulting solution is?

Answer 1

HCl is neutralised by an equal volume of NaOH. Each molecule of HCl provides one H+(aq) ion.

15eqL×11moleq×50 mL−110eqL×11moleq×100 mL=0

So, ideally, the resulting solution should be neutral.

Hope this will help you..... ✌

Answer 2

Explanation:

$0ln-=100×n/10

=100n/10

=10n

again,=50×n/5

=50n/5

=10n

therefore,10n+10n =20n

20n=0

n=-20