Question

when 100ml. of17%(w/w) solution of AgNO3 is mixed with 100ml of 5.85%(w/v)NaCl solution. the mass of precipitate formed will be​

Answer 1

Answer:

14.3 gram.

Explanation:

Since, the volume and percentage of (w/w) of silver nitrate is given so the mass of silver nitrate formed will be = 100/100*17= 17g of the silver nitrate.

So, the moles of silver nitrate will be 17/170(molar mass of the silver nitrate is 170g approximately) = 0.1 mole.

Similarly, mass of NaCl = 100/100*5.85 = 5.85 gram of NaCl so the moles will be = 5.85/58.5 where 58.5 is the molar mass of NaCl so the moles will be 0.1 moles.

From the equation we get that the precipitate will be AgCl whose molar mass is 143.3 gram/mol so the mass of the precipitate will be 0.1*143.3 = 14.3 gram of the AgCl will be precipitated.