Question

when 123 is added to a perfect square number, the new number so formed also becomes a perfect square. what is the square root of the new number?

Answer 1

Answer:

A/q, y 2 − x 2 = 123 = > ( y + x ) ( y − x ) = 41.3 ∴ y + x = 41... ( 1 ) and y − x = 3... ( 2 ) Now adding ( 1 ) and ( 2 ) , we get, y = 22 Putting the value of. ∴ The perfect sq .