Question

when 14.5 gram of SO2 reacts with 21 gram of O2 what will be the theoretical and percentage yield if the actual yield is 12 grams

Answer 1

Answer:

I am sharing with one sample do it from this

Explanation:

Sample CalculationTheoretical yield of product=12.641 g Na2S2O3x (1 mol 12.641 g Na2S2O3 / 126 g) x (1 mol Na2S2O3·5H2O / 1 mol Na2S2O3) = 0.1003254 mol Na2S2O3·5H2O0.1003254 mol Na2S2O3·5H2O x 248 g Na2S2O3·5H2O = 24.88 gPercentage yield= (10.391 g / 24.88 g) x 100 = 41.76%Discussion The theoretical yield of Na2S2O3· ...

Answer 2

Answer:

sample product= 12.641g Na2S2O3×(1 mol 12.641g Na 2S2O3 / 126 g) ×