When 150 gm of ice at 0°C is mixed with
300 gm of water at 50°C in a container, the
resulting temperature is
(L: = 3.34 * 10^5 J kg-, Sw = 4186 J kg-1 K-1)
(2) 3.7°C
(1) 2.7°C
(3) 5.7°C
(4) 6.7°C
Answers
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Answer:
(4) 6.7°C
(as per calculations answer is 6.6°C)
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