When 15g of a mixture of nacl and na2co3 is heated with dilute hcl 2.5g of co2 is evolved at ntp.calculate the percentage composition of the original mixture?
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Answered by
14
Only Na2CO3 will react in this case
Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O
Molar mass of Na2CO3 = 106
Molar mass of CO2 = 44
44g of CO2 is produced from 106g Na2CO3
What about 2.5g of CO2 = (2.5 x 106)/44
= 6.023 g
The original mixture has 6.023 g of Na2CO3
Percentage of Na2CO3 = 6.023/15 x 100 = 40.15%
Percentage of NaCl = 100 - 40.15 = 59.85%
Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O
Molar mass of Na2CO3 = 106
Molar mass of CO2 = 44
44g of CO2 is produced from 106g Na2CO3
What about 2.5g of CO2 = (2.5 x 106)/44
= 6.023 g
The original mixture has 6.023 g of Na2CO3
Percentage of Na2CO3 = 6.023/15 x 100 = 40.15%
Percentage of NaCl = 100 - 40.15 = 59.85%
Answered by
3
Answer:
Explanation:
Only Na2CO3 will react in this case
Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O
Molar mass of Na2CO3 = 106
Molar mass of CO2 = 44
44g of CO2 is produced from 106g Na2CO3
What about 2.5g of CO2 = (2.5 x 106)/44
= 6.023 g
The original mixture has 6.023 g of Na2CO3
Percentage of Na2CO3 = 6.023/15 x 100 = 40.15%
Percentage of NaCl = 100 - 40.15 = 59.85%
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