Question

when 165 ml of water at 22°c is mixed with 85 ml of water at 82°c, what is the final temperature? (assume that no heat is lost to the surroundings; d of water is 1 .00 g/ml)

Answer 1

Answer:

The Correct Answer is 42.2 degree celcius

Explanation:

Q=mcΔT , where Q denotes heat transfer, m denotes the mass of the substance, and T is the temperature change. The letter c denotes specific heat, which varies depending on the material and phase. The specific heat is the amount of energy required to raise the temperature of one kilogramme of mass by one degree Celsius.

q=mc∆t

For water q1 = q2

m1c∆t1 = m2c∆t2

If the density of water is 1.00 g/mL then m1 = 165 g and m2 = 85 g

165 × (tf - 22) = 85 × (82 - tf)

tf = 42.4 degrees Celsius