When 2.1 volt of potential difference is applied across ends of a lamp , then 0.21 ampere current Flows in its filament. Find resistance of filament of lamp
Answers
Answered by
14
V=IR
2.1=0.21×R
R=2.1/0.21
R=10 ohm
hope it will help you
2.1=0.21×R
R=2.1/0.21
R=10 ohm
hope it will help you
Answered by
5
Answer:
According to ohm's law
Explanation:
V=IR ,R=V/I R=2.1/0.21=10ohm
Similar questions