When 2.48g of white phosphorus is heated with 4.8g of NaOH and enough water produced 0.51g of PH3, the percentage yield of the reaction P4 + 3NaOH + 3H2O3NaH2PO2 + PH3 is
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Given:
Mass of phosphorous reacted = 2.48 gm
Mass of NaOH reacted = 4.8 gm
Mass of PH3 produced = 0.51 gm
To Find:
The percentage yield of the reaction.
Calculation:
- The given equation is:
P4 + 3NaOH + 3H2O → 3NaH2PO2 + PH3
- According to this reaction:
124 gm of Phosphorous reacts with 120 gm of NaOH to produce 34 gm of PH3.
⇒ 2.48 gm of phosphorous will react with 2.4 gm of NaOH to produce 0.68 gm of PH3
⇒ The theoretical yield = 0.68 gm
- The actual yield = 0.51 gm
- Percentage yield = (Actual yield/Theoretical Yield) × 100
⇒ % yield = (0.51/0.68) × 100
⇒ % yield = 75 %
- So, the percentage yield of the reaction is 75 %.
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