when 2 resistors are connected in series gives an equivalent resistance of 20 ohm, when connected in parallels gives 3.2 ohm then individual resistance is??
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Answer:
16 and 4 ohm
Explanation:
Let two resistance be r1 and r2
r1 + r2 = 20
(r1 × r2)÷(r1 + r2)= 3.2
Solving we get
Resistances are 16 and 4 ohm.
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