Question

When 2 resistors of 6Ω and 12Ω are connected to a battery of 6 v  in series combination, what will be the current passing through the circuit?​

Answer 1

ANSWER

Total current I flowing through the circuit I=  

R

V

​  

 

Here R=equivalentresistance=3.03Ω-----refer the figure given.

I  

total

​  

=  

3.03

5

​  

=1.65A

Since the resistors are in series connection (fig. B) current I will flow equally throughout the circuit.

Now calculating for voltage in resistor of 2Ω

V  

B

​  

=IR=3.30V, then current I flowing through 6Ω resistor I  

6  

Ω

​  

 

​  

=  

6

3.30

​  

=0.55

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Answer 2

Answer:

6+12=18ohm

I=R/V

l=18/6V

I=3ohm meter