When 22.4l of h2 is mixed with 11.2l of cl2 each at stp, the moles of hcl formed is equal to
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see both the below attachment it contains almost all the mole formulaes which you needed in this question refer them!
Then 22.4 liters would correspond to 1 mol of H2 and 11.2 liters of Cl2 would correspond to 0.5 mol. Here Cl2 is the limiting reagent. Therefore number of moles of HCl is 2 x 0.5 = 1 mol.
this is your answer just substitute the values in the formule,which is given in the attachment
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