When 2ml of Sodium sulphate is added to 2 ml of Barium chloride, white precipitate is formed. What is the colour of the precipitate? Name the precipitate & write the balanced chemical equation for the reaction.
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Sodium Sulphate reacts with Barium Chloride to form Sodium Chloride which is an aqueous solution and Barium Sulphate which is solid.
Barium Sulphate is a white crystalline solid.
It is insoluble in water.
Thus it formed as the precipitate in the Sodium Chloride solution.
The equation for the reaction is :
Na₂SO₄ (aq) + BaCl₂ (aq) -------> 2 NaCl (aq) + BaSO₄(s) ( white precipitate)
Barium Sulphate is a white crystalline solid.
It is insoluble in water.
Thus it formed as the precipitate in the Sodium Chloride solution.
The equation for the reaction is :
Na₂SO₄ (aq) + BaCl₂ (aq) -------> 2 NaCl (aq) + BaSO₄(s) ( white precipitate)
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When sodium sulphate and barium chloride is mixed, a double decomposition reaction occurs. That leads to the formation of sodium chloride (which remains in the solution) and barium sulphate (that settles down as white precipitate).As barium sulphate is insoluble in water so when barium ion meets sulphate it precipitates.
The color of barium sulphate is white crystalline solid.
The chemical reaction between the two can be written as
Na₂ So₄ (aq) + BaCl₂ (aq) ⇒ Ba SO₄ (s) + 2 NaCl (aq)
The color of barium sulphate is white crystalline solid.
The chemical reaction between the two can be written as
Na₂ So₄ (aq) + BaCl₂ (aq) ⇒ Ba SO₄ (s) + 2 NaCl (aq)
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