Question

When 2r3 - 9x2 + 10x – p is divided by (x + 1), the remainder is -24. Find the value of
P.
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Answer 1

$\\ Let p(x) = {2x}^{3} - {9x}^{2} + 10x - p \\ since \: remainder \: of \: p(x) \: when \: divided \: by \: x + 1 \: is \: - 24 \\ = > p( - 1) = - 24 \\ 2 {( - 1)}^{3} - 9 {( - 1)}^{2} + 10( - 1) - p = - 24 \\ - 2 - 9 - 10 + 24 = p \\ p = 3$