Question

When 2x^3 - x^2 - 3x + 5 is divided by 2x + 1, then the remainder is
(1) 6
(2) - 6

(3) 3

(4)0​

Answer 1

Step-by-step explanation:

2x + 1 = 0 , x = -1/2

The remainder

2(-1/2)³ - (-1/2)² - 3(-1/2) + 5

2(-1/8) - (1/4) + 3/2 + 5

-1/4 - 1/4 + 3/2 + 5

-1/2 + 3/2 + 5

1 + 5 = 6

The remainder is Six .

Answer 2

Answer:

(1) 6

Step-by-step explanation:

2x^3 - x^2 - 3x + 5= (2x^3+x^2)- (2x^2 + x)- (2x +1)+ 6

Those in brackets are divisible by 2x+1, so remainder is 6