when 3.0 gram of carbon is burnt in 8 gram of oxygen 11 gram of carbon dioxide is produced what mass of carbon dioxide will form when 3 gram of carbon is burnt in 50 gram of oxygen right law of chemical combination with will govern your answer
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Answer:-
C + O2 → CO2
3 g 8 g 11 g
Total mass of reactants = mass of C + mass of O = 3+8=11g
Total mass of reactants = total mass of products
Hence, the law of conservation of mass is proved.
Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3 : 8. Thus it also proves the law of constant proportions. 3 g of carbon must also combine with 8 g of oxygen only. This mean that (50 – 8) = 42 g of oxygen will remain unreacted.
C + O2 → CO2
3 g 8 g 11 g
Total mass of reactants = mass of C + mass of O = 3+8=11g
Total mass of reactants = total mass of products
Hence, the law of conservation of mass is proved.
Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3 : 8. Thus it also proves the law of constant proportions. 3 g of carbon must also combine with 8 g of oxygen only. This mean that (50 – 8) = 42 g of oxygen will remain unreacted.
yousuf1161:
thank you very very very very much
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When 3 gram of carbon is burnt in 50 gram of oxygen 11g of co2 produce
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