when 3.0g of carbon is burnt in 8.00g oxygen,11.00g of carbon dioxide is produced.what mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.00g of oxygen?which law of chemical combination will govern your answer?
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Total mass of reactants = mass of C + mass of O = 3+8=11g
Total mass of reactants = total mass of products
Hence, the law of conservation of mass is proved.
Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3 : 8. Thus it also proves the law of constant proportions. 3 g of carbon must also combine with 8 g of oxygen only. This mean that (50 – 8) = 42 g of oxygen will remain unreacted.
Hope it was Helpful
Total mass of reactants = total mass of products
Hence, the law of conservation of mass is proved.
Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3 : 8. Thus it also proves the law of constant proportions. 3 g of carbon must also combine with 8 g of oxygen only. This mean that (50 – 8) = 42 g of oxygen will remain unreacted.
Hope it was Helpful
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9
Molecular weight of CO₂
= molecular weight of carbon + molecular weight of dioxygen
= 12g + 32g = 44g
i.e 1 mole of carbon(6g) and 1 mole of dioxygen (32 g ) produce 44 g of carbon dioxide
then 1 mole of carbon burnt with 16 g of oxygen , it will produce 44× 16 /32 = 22 g of CO₂ .
so when 2 mole of carbon burnt with 16 g of oxygen , it will produce 22*2 g of CO₂
i.e 44g of CO₂ will be generated.
when 3.00 g of carbon is burnt in 50.00g of oxygen then the mass of carbon dioxide formed =53.00g
according to the law of conservation of mass the total mass before and after the reaction remains same.
3.00g +50.00g =53.00g
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