when 3.2 g of S is vaporised @ 450°C and 723 mm pressure, the vapour occupies a volume of 780 cm3 what is the molecular formula of S
in the conditions ?
Pls explain
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Answer: From ideal gas equation, pV=wMRT
∴ M=3.2×0.0821×760×1000×723723×780=256
∵ 32 g of sulphur has 1 atom of S.
∴ Molecular formula=S8
Explanation:
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