Chemistry, asked by parasharaditya032, 11 months ago

When 3.86 amperes current is passed through an electrolyte for 50 minutes, 2.4 grams of a covalent metal is deposited. The gram atomic mass of the metal ( in grams) is:

1 point

24

12

64

40

Answers

Answered by akibaftabsifmnil
2

Answer:

The quantity of electricity passed =Q(C)=I(A)×t(s)=3.86A×3000s=11580C.

The gram atomic weight of divalent metal = W

mol

g

Moles of electrons passed =

96500

mole

C

Q(C)

=

96500

mole

C

11580C

=

96500

11580

mole

The mass of divalent metal deposited = 2.4 g =atomicweightofmetal×moleratio×molesofelectronspassed

=W

mol

g

×

2mole

1molmetal

×

96500

11580

mole

W=40

mol

g

.

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