when 3 consecutive even integers are added . The sum is 0 . Find integers
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let the three integer be a+d,a and a-d
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Answer:
let x be one integer.so the other two integers are,x+1 and x+2
Step-by-step explanation:
it is given that
x+(x+1)+(x+2)=0
now,
x+x+1+x+2=0
3x+3=0
3x= -3
x= -3÷3= -1
∴ the integers are,
x= -1
x+1 = -1+1 = 0
x+2 = -1+2 = 1
hence their sum,
-1+0+1 = 0
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