Question

when (3y+1)(2y-3) = 6y² +ay-3 , what will be the value of a?

Answer 1

∴ Given Equation is (3y + 1)(2y - 3) = 6y^2 + ay - 3.

It can be written as,

⇒ 3y(2y - 3) + 1(2y - 3) = 6y^2 + ay - 3

⇒ 6y^2 - 9y + 2y - 3 = 6y^2 + ay - 3

⇒ 6y^2 - 9y + 2y - 3 - 6y^2 - ay + 3 = 0

⇒ -7y - ay = 0

⇒ -7y = ay

⇒ a = -7.

Therefore, the value of a = -7.

Hope it helps!

Answer 2

Answer:

answer (see the attached picture it's solved and the right answer is - 7) GOOD LUCK FOR MORE MATHS QUESTIONS