Question

when 4.8g of magnesium burns with excess oxygen, how much MgO is formed?

hint given : 2Mg +O2 = 2MgO

Answer 1

Howdy !!

your answer is --

write the given reaction in equation ,

2Mg + O2 ===> 2MgO

now ,

now , 2 mole of Mg formed 2 mole MgO

so, 1 mole of Mg formed 1 mole of MgO

now , 1 mole Mg = 24 g
and 1 mole MgO = 24+16 = 40 g

it means 24 g Mg => 40 g MgO

so, 4.8 g Mg => 40/24 × 4/8 = 8 g MgO


therefore , 4.8g of magnesium burns with excess oxygen then 8 g of MgO is produced.

hope it help you ========