when 4 unbaiaed coins are tossed , the probability of getting all heads is?
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All heads means only one chance, total outcomes 16,then answer is 1/16
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total number of events n(S) =(2)^4=16
all head coming events n(E) =1
p(E)=n(E)/n(S)=1/16
all head coming events n(E) =1
p(E)=n(E)/n(S)=1/16
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