Question

when 40% of a number is added to the square of the same number then it is increased to 4040% of itself, find the number. {Note:- answer is given 40 but i don't understand how}​

Answer 1

Answer:

40

Step-by-step explanation:

x^2 +40x/100 = 4040x/100

10x^2 + 4x = 404x

10x^2 = 400x

x= 0, 40

Answer 2

Answer:

The number whose 40% when added to its square increases its value by 4040% is 40.

Step-by-step explanation:

Let the original number be x.

It is given that 40% of the number is added to its own square. Hence, x² + 40% of x

This value is equal to 4040% of the original value, i.e., 4040% of x.

We have to find the original number, i.e., x

Representing the above statements mathematically, we get

x² + 40% of x = 4040% of x

x² + (40/100)x = (4040/100)x

x² + 0.4x = 40.4x

x² = 40.4x - 0.4x

x² = 40x

x = 40

Therefore, the original number is 40.

#SPJ2