Question

when 40g of an organic substance is dissolve in 600cm3 of water than the osmotic pressure of the obtained solution 8.2 atm at 273k​

Answer 1

Answer:

Osmotic pressure of the solution is given by,

π= CRT= (n/V) RT ------ (1)

where,

C = (n/V) having n = number of moles of solute

V = Volume of solution in litres

We can now substitute the value of number of moles and get the final formula

n = w/M = (Amount of substance)/(Molar mass of substance)

Now, osmotic pressure becomes,

π = (w×R×T)/(M×V)

Solving for M, we get M = (w ×R×T/(π×V))

Substituting the values,

M=

2.414×10

5

×10

−3

18×8.314×293

=182 g/mol