When ,4gm of naoh is dissloved in 10l of solution the ph?
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Answered by
1
Number of moles of NaOH = mass/molar mass = 4g / 40g/mol = 0.1mol
Molarity of NaOH = moles/volume in litres
= 0.1mol/10L = 10-2 M
Now,
[OH-] = [NaOH] = 10-2
[H+] = Kw/[OH-]
=10-14/10-2
= 10-12
pH = -log [H+]
= -log [10-12]
= 12
Molarity of NaOH = moles/volume in litres
= 0.1mol/10L = 10-2 M
Now,
[OH-] = [NaOH] = 10-2
[H+] = Kw/[OH-]
=10-14/10-2
= 10-12
pH = -log [H+]
= -log [10-12]
= 12
Answered by
0
Answer:
i think 10
Explanation:
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