When 5 grams of glucose is dissolved in 40 gram of water, calculate mole fraction of glucose
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Moles of glucose = 5 g / (180 g/mol)
= (1 / 36) mol
Moles of water = 40 g / (18 g/mol)
= (20 / 9) mol
Mole fraction of glucose = Moles of glucose / Total moles
= (1 / 36) / [1/36 + 20/9]
= 0.012
∴ Mole fraction of glucose in given solution is 0.012
= (1 / 36) mol
Moles of water = 40 g / (18 g/mol)
= (20 / 9) mol
Mole fraction of glucose = Moles of glucose / Total moles
= (1 / 36) / [1/36 + 20/9]
= 0.012
∴ Mole fraction of glucose in given solution is 0.012
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Answer:
Answer
0.0123
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