Question

When 5 times the larger of the two number is divided by the smaller quotient and remainder r2 as a 90 spectrally from a linear equation of two variable write it in standard form?

Answer 1

Let the larger number be x and smaller number be y Five times larger number = 5x When 5x is divided by y the quotient is 2 and remainder is 9. By division rule, we have Dividend = (divisor) × (quotient) + Remainder 5x = y(2) + 9 ⇒ 5x – 2y – 9 = 0 Put x = 3 and y = 3 in LHS 5x – 2y – 9 = 5(3) – 2(3) – 9 = 15 – 15 = 0 = RHS Hence x = 3 and y = 3 is one of the solution of the linear equation.

Answer 2

Let the larger number be x and smaller number be y 

Five times larger number = 5x

 When 5x is divided by y the quotient is 2 and remainder is 9. 

By division rule, we have 

Dividend = (divisor) × (quotient) + Remainder 

5x = y(2) + 9 ⇒ 5x – 2y – 9 = 0

Put x = 3 and y = 3

in LHS

 5x – 2y – 9 = 5(3) – 2(3) – 9                 

  = 15 – 15 = 0                 

= RHS Hence x = 3 and y = 3 is one of the solution of the linear equation.

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