when 50 ml of 2m solution of and N2O5 was heated 0.28 litre of O2 was formed after 30 mincalculate the concentrations of unreacted of N2O5 at that timealso find the average of reaction
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N
2
O
5
→N
2
O
4
+1/2O
2
50m
2
2Mm=
v
n
⇒n=m×v
=2(
1000
50
)=0.1
1 moles N
2
O
5
reacts to give 1 mole O
2
i.e : no
2
=
22.4
0.28
=0.0125moleO
2
0.0125moleN
2
O
5
use
Remaining = (0.1−0.0125) mol
=0.0875 mol
Explanation:
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