Question

when 56 g of burnt lime reacts with 18g water gives slaked lime. The weight of staked lime obtained will be?​

Answer 1

Answer:

Ca(OH)2 = Mole weight(Cao) + Mole Weight(H2o)

74g = 56g + 18g

Explanation:

Weight of a compound is calculated by the sum of its 2 reactants.

So, Mole Weight of Cao + Mole Weight of H2o = Mole Weight of [Ca(OH)2]