when 56 g of burnt lime reacts with 18g water gives slaked lime. The weight of staked lime obtained will be?
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Answer:
Ca(OH)2 = Mole weight(Cao) + Mole Weight(H2o)
74g = 56g + 18g
Explanation:
Weight of a compound is calculated by the sum of its 2 reactants.
So, Mole Weight of Cao + Mole Weight of H2o = Mole Weight of [Ca(OH)2]
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