when 6 boys were admitted and 6 girls left ,the percentage of boys increased from 60% to 75% .find the original number of boys and girls in the class
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Answered by
314
so the following is the required solution...
let me know if it helped u or not....
is it correct?
Let the number of boys and girls be x and y respectively.
Percentage of boys = 60%.
⇒ x / (x + y) = 60/100
⇒ 100 x = 60x + 60y
⇒ 40 x - 60 y = 0 ....(1)
6 boys were admitted ⇒ number of boys = (x + 6)
Percentage of boys = 75%
⇒ (x + 6) / (x + 6)+(y - 6) = 75/100
⇒ x - 3y = -2..... (2)
Solving equations (1)and (2), we get,
x = 24, y = 16.
Ans-:Therefore, original number of boys and girls are 24 and 16
let me know if it helped u or not....
is it correct?
Let the number of boys and girls be x and y respectively.
Percentage of boys = 60%.
⇒ x / (x + y) = 60/100
⇒ 100 x = 60x + 60y
⇒ 40 x - 60 y = 0 ....(1)
6 boys were admitted ⇒ number of boys = (x + 6)
Percentage of boys = 75%
⇒ (x + 6) / (x + 6)+(y - 6) = 75/100
⇒ x - 3y = -2..... (2)
Solving equations (1)and (2), we get,
x = 24, y = 16.
Ans-:Therefore, original number of boys and girls are 24 and 16
kairadas:
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Answered by
16
Step-by-step explanation:
let the number of boys be x
let the number of girls be y
ACCORDING TO THE QUESTION
no.of boys /total no.of girls and boys=x/x+y=%of boys
%of boys is 60
x/x+y=60/100
100x=60x+60y
40x-60y=0.........(1)
%of boys increased=75
x+6/(x+6)(y-6)=75/100
x-3y=-2..........(2)
solving (1)and(2) we get
x=24,y=16
no.of boys=24
no.of girls=16
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