Question

When 6 distinct toys are distributed at random to 3 persons the conditional probability that each gets at least 2 toys, given that each person has got at least one toy i?

Answer 1

sorry Ican't answer forgive me

Answer 2

Concept: Probability is the possibility of getting favorable outcome from total number of outcomes.

Find: Calculate conditional probability.

Solution:

Number of ways for each person gets at least one toy are-

=$3C_{0}(3)^{6} -3C_{1} (2)^{6}+3C_{2} x(1)^{6}$

=1X729-3X64+3

=729-192+3

=540

Number of ways for each person gets at least two toy are-

=$\frac{6!X3!}{2!X2!X2!X3!}$

=$\frac{720}{8}$

=90

Conditional probability of getting at least two toys for each person is $\frac{90}{540}$=$\frac{1}{6}$

Final answer: Conditional probability is 1/6.

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