Question

when 65-ohm resistor is connected to a 3 v battery. What will be the power dissipation of the resistor i

Answer 1

Answer:

$\frac{9}{65}$ Watt

Explanation:

Given :

when 65 Ω resistor is connected to a 3 V battery. What will be the power dissipation of the resistor .

Solution :

We know that,

Power dissipated = $\frac{(Voltage)^2}{Resistance}$

$P = \frac{V^2}{R}$

⇒ $P = \frac{3^2}{65} = \frac{9}{65}$ Watt.