Question

When 6x^4+8x^3+17x^2+21+7 is divided by 3x^2+4x+1 the remainder comes out ax+b find a and b?

Answer 1

Answer:

a=1

b=2

Step-by-step explanation:

when we divide 6x^4+8x^3+17x^2+21x+7 by 3x^2+4x+1

we get X+2 as a reminder

so a=1

b=2

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